Moving from rest, the car travels 25m in the first 5 seconds.

Moving from rest, the car travels 25m in the first 5 seconds. Calculate the distance traveled by the car in the tenth second after starting to move.

v0 = 0;
t1 = 5s,
s1 = 25m;
Sx -?
The distance traveled in the tenth second is equal to the difference between the paths traveled in 10s and 9s:
Sx = s10 – s9;
With uniformly accelerated motion without an initial speed, the path is determined from the formula
s = 1/2 * a * t ^ 2;
Hence:
Sx = 1/2 * a * 10 ^ 2 – 1/2 * a * 9 ^ 2 = 19/2 * a;
Find acceleration from
s1 = 1/2 * a * (t1) ^ 2;
a = 2 * s1 / (t1) ^ 2 = 2m / s ^ 2;
Sx = 19m.



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