Moving uniformly accelerated from a state of rest, the body in the fourth second of movement covered the path S = 14m.

Moving uniformly accelerated from a state of rest, the body in the fourth second of movement covered the path S = 14m. In what second from the beginning of movement the body will cover the path s = 26m.

With uniformly accelerated movement without initial speed, the paths traveled for equal time intervals (one second) differ according to the relationship:
S1: S2: S3: S4: S5: S6: S7 … = 1: 3: 5: 7: 9: 11: 13 …
For the fourth second of movement:
S1: S2: S3: S4: S5: S6: S7 … = … 14 … (2n – 1) = 1: 3: 5: 7: 9: 11: 13 …
Let’s make the proportion:
S4 / Sх = 14/26 = 7 / x.
x = 26 * 7/14 = 13 (corresponds to the seventh second of movement).
Answer: The body will travel 26 meters in the seventh second.