Moving with an acceleration of 0.2 m / s ^ 2, the body moved 20 meters in 10 seconds.

Moving with an acceleration of 0.2 m / s ^ 2, the body moved 20 meters in 10 seconds. Determine the speed of the body at the beginning and end of the path.

Initial data: a (body acceleration) = 0.2 m / s ^ 2; S (distance the body moved) = 20 m; t (time during which this body moved) = 10 s.

1) Let’s calculate the initial speed of the given body:

S = V0 * t + a * t ^ 2/2.

V0 * t = S – a * t ^ 2/2.

V0 = (S – a * t ^ 2/2) / t = (20 – 0.2 * 10 ^ 2/2) / 10 = 1 m / s.

2) Let’s calculate the speed of the body at the end of the movement:

V = V0 + a * t = 1 + 0.2 * 10 = 3 m / s.

Answer: The speed of the body at the beginning and at the end of the path is 1 m / s and 3 m / s, respectively.