Moving with an initial speed of 36 km / h, the car covered a distance of 105 m in 10 seconds.

Moving with an initial speed of 36 km / h, the car covered a distance of 105 m in 10 seconds. With what acceleration did the car move and what speed did it acquire at the end of the journey?

V0 = 36 km / h = 10 m / s.

t = 10 s.

S = 105 m.

a -?

V -?

With uniformly accelerated movement of the car, the distance traveled S and the acceleration a will be expressed by the formulas: S = V0 * t + a * t ^ 2/2, a = (V – V0) / t, S = (V ^ 2 – V0 ^ 2) / 2 * a, where V, V0 is its final and initial speed, a is the acceleration of the vehicle while driving.

a * t ^ 2/2 = S – V0 * t.

a = 2 * (S – V0 * t) / t2.

a = 2 * (10 ^ 5 m – 10 m / s * 10 s) / (10 s) ^ 2 = 0.1 m / s2.

V – V0 = a * t.

V = V0 + a * t.

V = 10 m / s + 0.1 m / s2 * 10 s = 11 m / s.

Answer: the car was moving with acceleration a = 0.1 m / s2 and its speed began to be V = 11 m / s.