Moving with uniform acceleration, the body travels a path s1 = 2m for the first t1 = 4s

| July 28, 2021 | education

Moving with uniform acceleration, the body travels a path s1 = 2m for the first t1 = 4s, and the next section of length s2 = 4m for t2 = 5s. Determine the acceleration of the body.

Let v0 be the initial velocity of the body, and its acceleration, then, according to the condition of the problem, the path traversed by the body in the first 4 s is equal to:

v0 * 4 + 8 * a = 2. (1)

After that, under the action of acceleration, the body in the next 5 s will acquire the speed v = v0 + a * t = v0 + 5 * a, and its path will be the expression:

(v0 + 4 * a) * 5 + 25 * a / 2 = 4. (2)

We got a system of two equations with two unknowns, solving which, we find that v0 = 11/30 = 0.37 m / s, and the acceleration a = 1/15 = 0.07 m / s².

Answer: the acceleration is 0.07 m / s².



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