# Moving with uniform acceleration, the body travels a path s1 = 2m for the first t1 = 4s

**Moving with uniform acceleration, the body travels a path s1 = 2m for the first t1 = 4s, and the next section of length s2 = 4m for t2 = 5s. Determine the acceleration of the body.**

Let v0 be the initial velocity of the body, and its acceleration, then, according to the condition of the problem, the path traversed by the body in the first 4 s is equal to:

v0 * 4 + 8 * a = 2. (1)

After that, under the action of acceleration, the body in the next 5 s will acquire the speed v = v0 + a * t = v0 + 5 * a, and its path will be the expression:

(v0 + 4 * a) * 5 + 25 * a / 2 = 4. (2)

We got a system of two equations with two unknowns, solving which, we find that v0 = 11/30 = 0.37 m / s, and the acceleration a = 1/15 = 0.07 m / s².

Answer: the acceleration is 0.07 m / s².