Natural limestone weighing 5 kg, containing 20% of impurities, was calcined. The resulting quicklime

Natural limestone weighing 5 kg, containing 20% of impurities, was calcined. The resulting quicklime was dissolved in water. Determine the mass of the slaked lime obtained.

Let’s calculate the available chemical amount of calcium carbonate substance.

M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol;

N CaCO3 = 5000 x 0.8 / 100 = 40 mol;

The same amount of slaked lime and then quicklime can be synthesized.

Let’s calculate the weight of 40 mol of slaked lime.

M Ca (OH) 2 = 40 + 16 x 2 + 2 = 74 grams / mol;

m Ca (OH) 2 = 74 x 40 = 2 960 grams;