ND is the height of the triangle MNK; MD = DK. Prove that triangle MND = KND.

Since, according to the condition, ND is the height of the triangle MNK, then the angle NDK = NDM = 90.

Then the triangles MND and KND are rectangular.

Let us prove that the triangles MND and KND are equal.

The leg ND of triangles is common, according to the condition, MD = DK, then right-angled triangles MND and KND are equal in two legs – the first sign of equality of right-angled triangles, which was required to prove.



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