Nitric oxide (v) weighing 22.6 g was dissolved in 500 g of water.

Nitric oxide (v) weighing 22.6 g was dissolved in 500 g of water. Determinant of the mass fraction of nitric acid in the resulting solution.

Given:
m (N2O5) = 22.6 g
m (H2O) = 500 g
To find:
w (HNO3)
Decision:
N2O5 + H2O = 2HNO3
m solution (HNO3) = 22.6 g + 500 g = 522.6 g
n (N2O5) = m / M = 22.6 g / 108 g / mol = 0.21 mol
n (N2O5): n (HNO3) = 1: 2
n (HNO3) = 0.21 mol * 2 = 0.42 mol
m in islands (HNO3) = n * M = 0.42 mol * 63 g / mol = 26.46 g
w (HNO3) = m in-va / m p-ra = 26.46 g / 522.6 g = 0.0506 * 100% = 5.06%
Answer: 5.06%