Nitrogen weighing 300 g at a temperature of 7 degrees exerts a pressure on the walls of the vesse

Nitrogen weighing 300 g at a temperature of 7 degrees exerts a pressure on the walls of the vessel equal to 83 kPa. What is the volume of gas?

To find the volume occupied by nitrogen in the vessel used, we apply the Mendeleev-Clapeyron equation: V = m * R * T / (MN2 * P).

Variables and constants: m is the mass of nitrogen in the vessel used (m = 300 g = 0.3 kg); R – universal gas constant (R = 8.31 J / (K * mol)); T – abs. temperature (Т = 280 К (7 ºС)); MN2 – molar mass of nitrogen (MN2 = 2.8 * 10 ^ -2 kg / mol); P – pressure on the walls (P = 83 kPa = 83 * 10 ^ 3 Pa).

Calculation: V = m * R * T / (MN2 * P) = 0.3 * 8.31 * 280 / (2.8 * 10 ^ -2 * 83 * 10 ^ 3) = 0.3 m3.

Answer: Gas occupies a volume of 0.3 m3 in the used vessel.