# Nitrogen with a mass of m = 3.5 kg occupies at a temperature of T1 = 330 K, V1 = 0.8m ^ 3. As a result of adiabatic

September 12, 2021 | education

| **Nitrogen with a mass of m = 3.5 kg occupies at a temperature of T1 = 330 K, V1 = 0.8m ^ 3. As a result of adiabatic compression, the gas pressure increased 3 times. Determine the final temperature.**

To find the value of the final temperature of taken nitrogen, we use the formula (Poisson’s equation): T2 = T1 * (P2 / P1) ^ (k – 1) / k.

Constants and variables: T1 – initial temperature of taken nitrogen (T1 = 330 K); Р1 / Р2 – change (increase) of pressure (Р2 / Р1 = 3); k – adiabatic exponent (k = 1.4).

Let’s perform the calculation: T2 = T1 * (P2 / P1) ^ (k – 1) / k = 330 * 3 ^ (1.4 – 1) / 1.4 = 451.7 K.

Answer: The temperature of taken nitrogen after adiabatic compression became equal to 451.7 K.

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