O is the center of the circle, AB and AC are equal chords, B = 34, find OAC.

Let us construct from point O the radii OС, OB and OA to the edges of the chords AC and AB.

By condition, the chord AC = AB.

Then in triangles OAC and OAB, AC = AB, OC = OA = OB, and then triangles OAC and OAB are equal on three sides.

Triangles ОАВ and ОАС are equal and isosceles, since ОА = ОВ = OC = R, then the angle ОАС = OCB = ОВА = OCA = 34.

Answer: The OAC angle is 34.