O is the center of the circle, AB and AC are equal chords, the angle AOB = 70 degrees. Find the angle OAC.

In triangles AOB and AOC AB = AC by condition, OB = OA = OC as the radii of a circle, then triangles AOB and AOC are equal on three sides.

Then the angle AOC = AOB = 70.

The AOC triangle is isosceles with the AC base, then the angle OAC = OCA = (180 – AOC) / 2 = (180 – 70) / 2 = 55.

Answer: The value of the angle OAC is 55.



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