Of the two cities, the distance between them is 135 km. 2 cyclists left at the same time to meet each other. The speed of one of them is 15 km / h, what is the speed of the second if it is known that they met after 5 hours. after check-out.
Distance – 135 km;
Speed of 1 cyclist – 15 km / h;
Cyclist speed 2 -? km / h;
Time before meeting – 5 hours.
Since the path of 135 km the cyclists traveled together before the meeting, which took place 5 hours after the simultaneous departure, then, denoting the speed of 2 km / h, we calculate the speed of their convergence as (x + 15) km / h. Knowing that the path is the product of speed and time, we compose the equation:
(x + 15) * 5 = 135;
5x + 75 = 135;
5x = 135 – 75;
5x = 60;
x = 60/5 = 12 (km / h) – speed 2 speed.
Answer: 12 km / h.
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