Oil is pumped out of a well 500 m deep using a pump that consumes a power of 10 kW. What is the efficiency

Oil is pumped out of a well 500 m deep using a pump that consumes a power of 10 kW. What is the efficiency of the pump if 96 kg of oil is supplied to the surface of the earth in one minute of its operation?

These tasks: h (borehole depth) = 500 m; N (power consumed by the pump used) = 10 kW (10 * 10 ^ 3 W); t (running time) = 1 min = 60 s; m (mass of oil supplied) = 96 kg.

Reference values: according to the condition g (gravitational acceleration) ≈ 10 m / s2.

The efficiency of the pump used is calculated by the formula: η = Ap / Az = ΔEp / (N * t) = m * g * h / (N * t).

Let’s calculate: η = 96 * 10 * 500 / (10 * 10 ^ 3 * 60) = 0.8 (80%).

Answer: The pump for pumping oil has an efficiency of 80%.