On a 60 cm segment AC, mark the points E and F so that AE equals 32 cm FС 34, which is equal

On a 60 cm segment AC, mark the points E and F so that AE equals 32 cm FС 34, which is equal to the length of the segment EF.

Let’s find the sum of the lengths of the segments AE and FС.

32 + 34 = 66 (cm).

The length of these two segments is greater than the length of the segment AC. It follows that the point E is closer to the point A than to the point F, and this, in turn, means that the segment EF is included in both the segment AE and the segment FC. So, you need to subtract the length of the segment AE from the sum of AE and FС and divide the result in half:

66 – 60 = 6.

6: 2 = 3 (cm).

Answer: the segment EF is 3 cm.



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