On a 600 watt hotplate, two liters of water are heated from 15 ° C to 100 ° C in 40 minutes. Determine the efficiency installation.
| February 14, 2021 | education
The efficiency will be determined by the formula
Efficiency = Q / A.
Quantity of heat
Q = c * m * (t2 – t1);
s = 4200 J / (kg * ° C);
m = 2 * 1000/1000 = 2 kg;
Q = 4200 * 2 * (100 – 15) = 714000 J.
Job
A = N * T;
T = 40 * 60 = 2400 s;
A = 600 * 2400 = 1440000 J.
Determine the efficiency
Efficiency = 714000/1440000 = 0.496.
Answer: 0.496.
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