On a body located on a horizontal plane, 2 horizontal forces act, the moduli of which are equal to f1 = 6 f2 = 8

On a body located on a horizontal plane, 2 horizontal forces act, the moduli of which are equal to f1 = 6 f2 = 8, if the body weight is 10 kg, then its acceleration is?

Given:
F1 = 6H
F2 = 8H
m = 10kg
Find: a =?
Decision :
Let’s direct the OX axis to the right
F1 is directed to the left, F2 is directed to the right, then the resultant of the forces F2-F1 in projection on OX
According to Newton’s second law, Fр = ma
Hence a = Fр / m
a = F2-F1 / m
a = 8H-6H / 10kg
a = 2N / 10kg = 0.2 N / kg
Answer: a = 0.2 N / kg.