On a body weighing 1 kg lying on a smooth horizontal plane, a force of 2N begins to act at an angle of 60 to the Vertical

On a body weighing 1 kg lying on a smooth horizontal plane, a force of 2N begins to act at an angle of 60 to the Vertical, find the body’s acceleration modulus.

Condition:
m = 1 kg
F = 2 H
α = 60 °
To find :
a-?
Decision :
F = ma (2 Newton’s law).
At an angle:
F * cos α = ma.
a = F * cos α / m.
cos 60 ° = 1/2 = 0.5.
a = 2 * 0.5 / 1 = 1 (m / s ^ 2).
Answer: 1 m / s ^ 2.