On a car with a mass of 2 tons, moving uniformly at a speed of 6 m / s, sand with a mass

On a car with a mass of 2 tons, moving uniformly at a speed of 6 m / s, sand with a mass of 1 ton was poured from above at what speed the car would move.

According to the law of conservation of momentum:
m1V1 = (m1 + m2) U1, where m1 is the mass of the car (m1 = 2 t = 2000 kg), m2 is the mass of sand (m2 = 1 t = 1000 kg); V1 is the initial speed of the car (V1 = 6 m / s), U1 is the speed of the car with sand (m / s).
Let’s calculate the speed of the car with sand:
U1 = m1V1 / (m1 + m2) = 2000 * 6 / (2000 + 1000) = 2000 * 6/3000 = 12000/3000 = 4 m / s.
Answer: The car will move at a speed of 4 m / s.