On a certain section of the chain, the train speed decreases from 80 km / h to 60 km / h.

On a certain section of the chain, the train speed decreases from 80 km / h to 60 km / h. At the same time, the acceleration of the train is 0.21 m / s². How long does this change in speed take?

Initial data: Vн (initial train speed) = 80 km / h (22.222 m / s); Vк (final speed of the train) = 60 km / h (16.667 m / s); a (train acceleration on a certain section of track) = -0.21 m / s2 (slow motion).

The time during which the speed change occurred can be calculated by the formula: Vк = Vн – a * t, whence t = (Vк – Vн) / а.

Let’s perform the calculation: t = (16.667 – 22.222) / (-0.21) ≈ 26.5 s.

Answer: The change in train speed occurred in 26.5 s.



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