On a conductor 30 cm long, located perpendicular to the lines of magnetic induction, a force of 0.6N acts.

On a conductor 30 cm long, located perpendicular to the lines of magnetic induction, a force of 0.6N acts. Find the current in the conductor if the magnetic field induction is 400mTL. Find the mass of the conductor, provided that it is in equilibrium in a given magnetic field.

Let’s write the formula for solving the problem:
I = F / B * L;
Substitute the values in the formula and calculate:
I = 0.6 / 0.3 * 0.4;
I = 5 A;
We also know that Mg = 0.6.
Now we find M, write down the formula for solving the problem:
M = 0.6 / g;
Let’s substitute:
M = 0.6 / 10;
M = 0.06 kg;
M = 60 gr.
Answer: M = 60 gr.