On a conductor with a length of l = 0.25 m, located perpendicular to the lines of force of the magnetic field

On a conductor with a length of l = 0.25 m, located perpendicular to the lines of force of the magnetic field, the force is F = 5 * 10-3 N. What current flows through the conductor in if the magnetic field induction is B = 10 T?

L = 0.25 m.

∠α = 90 °.

Famp = 5 * 10-3 N.

B = 10 T.

I -?

On a conductor with a current, in a magnetic field, the Ampere force Famp acts, the value of which is determined by the formula: Famp = I * B * L * sinα. Where I is the current in the conductor, B is the magnetic induction of the field, L is the length of the conductor, ∠α is the angle between the direction of the current and the vector of magnetic induction B.

We express the current strength in the conductor by the formula: I = Famp / B * L * sinα.

I = 5 * 10-3 N / 10 T * 0.25 m * sin90 ° = 0.002 A = 2 mA.

Answer: the current in the conductor is I = 2 mA.