On a cord thrown over a stationary block, weights of 300 g and 340 g are suspended.

On a cord thrown over a stationary block, weights of 300 g and 340 g are suspended. For 2 seconds after the start of movement, each load traveled a path of 1.2 m. According to the experience, find the acceleration of gravity.

Given:

m1 = 300 grams = 0.3 kilograms;

m2 = 340 grams = 0.34 kilograms;

t = 2 seconds;

L = 1.2 meters.

It is required to determine g (m / s2) – the acceleration of gravity.

Since the condition of the problem is not specified, we do not take into account the mass of the block and consider that the thread is not stretched.

Let’s find the acceleration of the cargo system:

a = 2 * L / t ^ 2 = 2 * 1.2 / 2 ^ 2 = 2.4 / 4 = 0.6 m / s2.

According to Newton’s second law, we have:

m2 * g – T = m2 * a;

T – m1 * g = m1 * a, hence: T = m1 * g + m1 * a.

m2 * g – m1 * g – m1 * a = m2 * a;

g * (m2 – m1) = a * (m2 + m1);

g = a * (m2 + m1) / (m2 – m1) = 0.6 * (0.34 + 0.3) / (0.34 – 0.3) =

= 0.6 * 0.64 / 0.04 = 0.384 / 0.04 = 9.6 m / s2.

Answer: according to experience, the acceleration of gravity is 9.6 m / s2.