On a gas burner it is necessary to melt tin weighing 0, 20 kg, which is at the melting temperature.

| February 15, 2021 | education

On a gas burner it is necessary to melt tin weighing 0, 20 kg, which is at the melting temperature. Determine the volume of burnt natural gas if the heat loss to the environment was 40% (specific heat of combustion of natural gas q = 35.5 MJ / m3, specific heat of fusion of tin = 6.03 * 10 ^ 4)

Problem data: m1 (mass of tin for melting) = 0.2 kg; η (process efficiency) = 60% or 0.6 (40% loss).

Constants: according to the condition q (specific heat of combustion of natural gas) = 35.5 * 10 ^ 6 J / m3; λ (specific heat of fusion of tin) = 6.03 * 104 J / kg.

We express the required volume of burnt natural gas from the formula: η = λ * m1 / (q * V2) and V2 = λ * m1 / (η * q).

Let’s make the calculation: V2 = 6.03 * 10 ^ 4 * 0.2 / (0.6 * 35.5 * 10 ^ 6) = 5.66 * 10 ^ -4 m3.

Answer: The required volume of burnt natural gas is 5.66 * 10 ^ -4 m3.



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