On a horizontal road, the car makes a turn with a radius of 16m. Determine the coefficient of friction of the tires
| February 24, 2021 | education
On a horizontal road, the car makes a turn with a radius of 16m. Determine the coefficient of friction of the tires on the asphalt if it moves at a speed of 36 km / h.
R = 16 m.
V = 36 km / h = 10 m / s.
g = 9.8 m / s ^ 2.
μ -?
Let’s write 2 Newton’s law in projections on the horizontal axis: m * a = Ftr.
The centripetal acceleration of the body a is determined by the formula: a = V ^ 2 / R.
We express the friction force by the formula: Ftr = μ * m * g.
m * V ^ 2 / R = μ * m * g.
μ = V ^ 2 / R * g.
μ = (10 m / s) ^ 2/16 m * 9.8 m / s ^ 2 = 0.64.
Answer: μ = 0.64.
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