On a lever with shoulders of 15 cm and 30 cm, two cups are balanced. Will the lever remain in balance

On a lever with shoulders of 15 cm and 30 cm, two cups are balanced. Will the lever remain in balance if we put 100 grams of weights on each cup?

F1 * l1 = F2 * l2, where F1 is the force with which the mass of the first cup acts on the shoulder l1 (F1 = Fт = m1 * g), l1 is the smaller shoulder (l1 = 15 cm), F2 is the force with which the mass the second cup acts on the shoulder l2 (F2 = Ft = m2 * g), l2 – the larger shoulder (l2 = 30 cm).
m1 * g * l1 = m2 * g * l2.
m1 * 15 = m2 * 30.
m1 = 2m2 – the condition for the balance of the lever.
If you put 100 grams on each cup:
m1 + 100 ≠ 2 (m2 + 100).
m1 + 100 ≠ 2m2 + 200.
m1 ≠ 2m2 + 100.
Answer: The lever will not be in balance.