On a section of a straight conductor 50 cm long in a uniform magnetic field with an induction of 2 TL

On a section of a straight conductor 50 cm long in a uniform magnetic field with an induction of 2 TL at a current in the conductor of 30 A and the direction of the magnetic field induction vector at an angle of 30 to the conductor, an ampere force is applied equal to ..

L = 50cm = 0.5m.

B = 2 T.

I = 30 A.

∠α = 30 °.

Fump -?

If you place a conductor of length L in a magnetic field with induction B and pass an electric current with a force I through it, then the Ampere force Famp will begin to act on it. Ampere force Famp is determined by the formula: Famp = I * B * L * sinα, where ∠α is the angle between the direction of the current in the conductor and the vector of magnetic induction B.

Famp = 30 A * 2 T * 0.5 m * sin30 ° = 15 N.

The direction of the Ampere Famp force is determined by the left hand rule. We place the left hand so that the four extended fingers are directed in the direction of the current I, the magnetic induction vector B enters the palm, the thumb will show the direction of the Ampere Famp force.

Answer: Ampere force Famp = 15 N. acts on a conductor with current.