On a sleigh weighing 300 kg we put a box whose gravity is 500 N. With what force the sleigh acts on the road.

Given:

m1 = 300 kilograms – the weight of the sleigh;

F2 = 500 Newtons – the force of gravity acting on the load, which was placed on the sled;

g = 10 N / kg (Newton per kilogram) – acceleration due to gravity (rounded off value).

It is required to determine F (Newton) – with what force the sleigh acts on the road.

By the condition of the problem, we assume that the sleigh is on a strictly horizontal surface.

Then, the force of gravity acting on the sled itself will be equal to:

F1 = m1 * g = 300 * 10 = 3000 Newtons.

The total pressure force will be equal to:

F = F1 + F2 = 3000 + 500 = 3500 Newton (3.5 kN).

Answer: a sled with a load press on the road with a force equal to 3500 Newtons.



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