On a spring, a body weighing 3kg750g. The gesture coefficient is 200. Find the final length

On a spring, a body weighing 3kg750g. The gesture coefficient is 200. Find the final length of the spring. Its initial length is 40 cm.

To find out the final length of the taken spring, consider the equality: mt * a = mt * g = Fel (elastic force) = k * Δx = k * (Δxk – Δxn), whence we express: Δxk – Δxn = mt * g / k and Δxk = Δxn + mt * g / k.

Const: g – acceleration due to gravity (approx. G ≈ 10 m / s2).

Data: Δxn – the initial length of the taken spring (Δxn = 40 cm, in SI system Δxn = 0.4 m); mt is the mass of the attached body (mt = 3 kg 750 g, in SI mt = 3.75 kg); k – rigidity of the taken spring (k = 200 N / m).

Let’s perform the calculation: Δxk = Δxn + mt * g / k = 0.4 + 3.75 * 10/200 = 0.5875 m = 587.5 mm.

Answer: The final length of the taken spring is 587.5 mm.