On a spring of stiffness of 100 N / m, the bar is pulled evenly over a distance of 2 m, find F of elasticity.

Initial data: k (value of spring stiffness) = 100 N / m; Δl (spring extension) = 2 m.

The force of elasticity that will act on the spring during uniform stretching can be determined by Hooke’s law: Fel = k * Δl.

Let’s calculate the elastic force: Fel = 100 * 2 = 200 N.

Answer: An elastic force of 200 N. acts on the spring.

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