On a spring with a stiffness of 100 N / m, a weight weighing 0.4 kg oscillates. Determine the period

On a spring with a stiffness of 100 N / m, a weight weighing 0.4 kg oscillates. Determine the period of oscillation of the weight on the spring.

These tasks: k (spring rate) = 100 N / m; m (the mass of the load that vibrates on the taken spring) = 0.4 kg.

The period of oscillation of the load on the spring (spring pendulum) is calculated by the formula: T = 2 * Π * √ (m / k).

Let’s perform the calculation: T = 2 * 3.14 * √ (0.4 / 100) ≈ 0.397 s.

Answer: A load weighing 0.4 kg will oscillate with a period of 0.397 s.



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