On a stove, water was heated with a volume of 2 liters from 10 ° C to 100 ° C. Some of the water

On a stove, water was heated with a volume of 2 liters from 10 ° C to 100 ° C. Some of the water has boiled away. Determine the mass of water that has turned into steam, if the efficiency of the primus is 40%, and the mass of consumed kerosene is 60 grams.

Qк = q * m1, q – beats. heat of combustion. (q = 4.6 * 107 J / kg), m1 – mass (m1 = 0.06 kg).

Qk = 4.6 * 107 * 0.06 = 2760000 J.

Qv = Q1 + Q2.

Q1 = С * m * (tк – tн), С – beats. heat capacity (С = 4200 J / (kg * К)), m – mass (m = 2 l = 2 kg), tк = 100 ºС, tн = 10 ºС.

Q2 = L * m2, L – beats. heat steam (L = 2.3 * 106 J / kg).

Q = 4200 * 2 * (100 – 10) + 2.3 * 106 * m2 = 756000 + 2.3 * 106 * m2.

ηQк = Q.

0.4 * 2760000 = 756000 + 2.3 * 106 * m2.

2.3 * 106 * m2 = 348000.

m2 = 0.151 kg = 151 g.



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