On a straight conductor 0.5 m long, located at an angle of 30 degrees to the lines of the magnetic induction vector
| May 5, 2021 | education
On a straight conductor 0.5 m long, located at an angle of 30 degrees to the lines of the magnetic induction vector, a force of 0.15 N acts. Determine the current strength in the conductor if the magnetic induction is 20 mt
Given: l (straight conductor length) = 0.5 m; α (the angle at which the straight conductor is located to the lines of magnetic induction) = 30º; Fa (Ampere force that acts on the conductor) = 0.15 N; T (value of magnetic induction) = 20 mT (20 * 10 ^ -3 T).
We calculate the current in the conductor using Ampere’s law: Fa = B * I * l * sinα, whence I = Fa / (B * l * sinα).
Calculation: I = 0.15 / (20 * 10 ^ -3 * 0.5 * sin 30º) = 30 A.
Answer: The current in a straight conductor is 30 A.
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