On a straight line segment of the trajectory with a length of 150 meters, the speed of a car weighing 1000

On a straight line segment of the trajectory with a length of 150 meters, the speed of a car weighing 1000 kg increased from 0 to 108 km / h. Calculate the value of the constant force that caused this change in speed.

S = 150 m.
m = 1000 kg.
V0 = 0 m / s.
V = 108 km / h = 30 m / s.
F -?
According to Newton’s 2 law: F = m * a, where m is the mass of the body, and is the acceleration of the body.
a = (V ^ 2 – V0 ^ 2) / 2 * S.
Since V0 = 0 m / s, then a = V ^ 2/2 * S.
F = m * V ^ 2/2 * S.
F = 1000 kg * (30m / s) ^ 2/2 * 150 m = 3000 N.
Answer: the car moves under the action of a force F = 3000 N.