On a triangle ABC, AD-bisector, angle C is 50 degrees, angle CAD is 28 degrees. Find angle B.

1. In geometry it is known that:

a) bisector – this is a ray with the beginning at the apex of the angle, which divides the angle into two equal parts;

b) the sum of the angles of the triangle is 180 °.

2. In the problem statement the following is given: angle С = 50 °, angle CAD = 28 °.

So the angle A, divided by the bisector in half, is twice its half and is 2 * 28 ° = 56 °.

3. Angle B is calculated as the difference between 180 ° and the sum of the angles A and C, that is

180 ° – (A + B) = 180 ° – (56 ° + 50 °) = 180 ° – 106 ° = 74 °.

Answer: In a triangle, the third angle B is 74 °.