On an unknown planet, a pendulum 80 cm long made 36 complete oscillations in 1 min.

On an unknown planet, a pendulum 80 cm long made 36 complete oscillations in 1 min. What is the acceleration of gravity on this planet?

l = 80 cm = 0.8 m.

N = 36.

t = 1 min = 60 s.

g -?

Let us express the period of the mathematical pendulum by the formulas: T = 2 * P * √l / √g and T = t / N.

2 * P * √l / √g = t / N.

√g = 2 * P * N * √l / t.

g = 4 * P ^ 2 * N ^ 2 * l / t2.

g = 4 * (3.14) ^ 2 * (36) ^ 2 * 0.8 m / (60 s) ^ 2 = 11.4 m / s2.

Answer: the acceleration of gravity on the planet was g = 11.4 m / s2.



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