On cooling 200 g of a 25% salt solution, 32.9 g of this salt was released. the mass fraction of salt in the remaining solution is?

1. Calculate the total mass of salt in the original solution:

mtot (salt) = w (salt) * mout (solution);

mtotal (salt) = 0.25 * 200 = 50 g;

2.determine the mass of the salt remaining in the solution:

bridge (salts) = mtot (salts) – msec (salts);

bridge (salt) = 50 – 32.9 = 17.1 g;

3. find the mass of the remaining solution:

bridge (solution) = mout (solution) – m release (salt) = 200 – 32.9 = 167.1 g;

4. find the mass fraction of the remaining salt:

wrest = bridge (salt): bridge (solution) = 17.1: 167.1 = 0.1023 or 10.23%.

Answer: 10.23%.