On Earth, a mathematical pendulum oscillates with a period of 1 s. What will be the period of oscillation of this pendulum

On Earth, a mathematical pendulum oscillates with a period of 1 s. What will be the period of oscillation of this pendulum on Mars, where the acceleration of gravity is about 2.6 times less than on Earth?

Let us find the acceleration of gravity on Mars (g2) from the data in the condition.
Free fall acceleration on Earth-g1
g1 = 2.6g2
g2 = g1 / 2.6
T = 2pi * √ (l / g)
T2 = 6.28 * √ (l / g1 * 1 / 2.6)
T2 = 0.62 * T1 = 0.62c



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