On one plate of the capacitor there is a positive charge of 0.2 C, on the other negative charge of -0.2 C.

On one plate of the capacitor there is a positive charge of 0.2 C, on the other negative charge of -0.2 C. The electrical capacity of the capacitor is 10 ^ 4 μF. What is the tension between the plates?

Task data: qp (charge on the positive plate) = 0.2 C; qо (charge on the negative plate) = -0.2 C; C (electrical capacity of the capacitor in question) = 104 μF (10-2 F).

The voltage between the plates of the capacitor under consideration can be expressed from the formula: C = q / U, whence U = q / C.

Calculation: U = 0.2 / 10-2 = 20 V.

Answer: The effective voltage between the plates of the capacitor in question is 20 V.