On the AC side of this triangle ABC, construct a point O so that the area of triangle ABO is one quarter of the area of triangle ABC.
| January 16, 2021 | education
The area of the triangle ABC = S (ABC) = AC * BH / 2, where BH is the height of the triangle, lowered to the base of the AC.
The area of the smaller triangle ABO = S (ABO) = AO * BH / 2. S (ABO) = S (ABC) / 4 = [(AB * BH) / 2] / 4 = (AB / 4) * BH / 2.
Hence, it is necessary that AO = AC / 4- divide AC by 2 and another 2, and we get the point O.
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