On the BC side of the parallelogram ABCD, point M is taken so that AB = BM.
| September 26, 2021 | education
On the BC side of the parallelogram ABCD, point M is taken so that AB = BM. Prove one hundred AM – bisector of the angle BAD.
By the problem statement AB = BM. Then triangle ABM is isosceles. But, the BAM angle is equal to the BMA angle (angles at the base of an isosceles triangle). The angles BMA and MAD are also equal (internal versatile for parallel lines BC and AD). Then the angle BAM is equal to the angle MAD. This means that AM is the bisector of the angle BAD.
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