On the BC side of the square ABCD, point K was marked so that AK = 2BK. Find the angle KAD.

After drawing a segment of AK, a right-angled triangle is obtained. In the resulting triangle, the side of the ВK is the opposite leg for the angle KAD? the AK side itself is the hypotenuse. Find the sine of the angle KAD
The sine of the angle sin (A) is the ratio of the opposite leg to the hypotenuse.
sinKAD = BK / AK
Let ВK be equal to x, then, according to the conditions of the problem, AK will be 2x

sinKAD = x / 2x
sinKAD = 1/2

From the tables, we find that the sin of the angle is 1/2 in the case when the angle is 30 degrees.

Answer: The KAD angle is 30 degrees.



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