On the bridge 400 meters long there is a train for 30 seconds, and past a man – 10 seconds.

On the bridge 400 meters long there is a train for 30 seconds, and past a man – 10 seconds. Find the length and speed of the train.

Lm = 400 m.

tm = 30 s.

tch = 10 s.

Lп -?

Vп -?

We express the speed of the train Vp by the formula: Vp = Lp / tch.

The time of movement of the train on the bridge is expressed by the formula: tm = (Lm + Lp) / Vp.

Vp = (Lm + Lp) / tm.

Lp / tch = (Lm + Lp) / tm.

Lm * tch + Lp * tch = Lp * tm.

Lm * tch = Lp * (tm – tch).

The length of the train Lp will be determined by the formula: Lp = Lm * tch / (tm – tch).

Lp = 400 m * 10 s / (30 s – 10 s = 200 m.

Vp = 200 m / 10 s = 20 m / s.

Answer: a train with a length of Lp = 200 m moves along the bridge with a speed of Vp = 20 m / s.



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