On the floor of the elevator, which starts moving vertically upward with an acceleration of 0.5 ms2

On the floor of the elevator, which starts moving vertically upward with an acceleration of 0.5 ms2, there is a load weighing 30 kg. What is the modulus of this load.

Given:

a = 0.5 m / s2 (meter per second squared) is the acceleration with which the elevator moves;

m = 30 kilograms – the mass of the load lying on the floor of the elevator;

g = 10 Newtons per kilogram – acceleration of gravity (approximate value).

It is required to determine P (Newton) – the modulus of the weight of this load.

Since, according to the condition of the problem, the movement of the elevator is directed vertically upwards, in order to determine the modulus of body weight, it is necessary to use the following formula:

P = m * (g + a) = 30 * (10 + 0.5) = 30 * 10.5 = 315 Newton.

Answer: body weight is 315 Newtons.