On the floor of the freight elevator there is a load weighing 0.5 tons, what is the weight of this load if the elevator moves evenly.
| December 13, 2020 | education
Since there is no acceleration (except for the acceleration of gravity), then P = F = mg = 0.5 tons * 9.81 m / s ^ 2 = 500 kg * 9.81 m / s ^ 2 = 4905 kg (can be rounded up to 5 tons).
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