On the ground lies a chain 4 meters long and weighing 10 kg. the chain is lifted at one end so that

On the ground lies a chain 4 meters long and weighing 10 kg. the chain is lifted at one end so that it is lifted off the ground. What work is done when lifting?

Problem data: l (length of the considered chain) = 4 m; m (chain weight) = 10 kg; h (change in the center of mass of the chain when lifting at one of the ends) = 0.5l.

Reference values: g (acceleration due to gravity) ≈ 10 m / s2.

The work done when lifting the chain under consideration is equal to the change in the potential energy of its center of gravity: A = ΔEp = m * g * h = m * g * 0.5l.

Let’s make a calculation: A = 10 * 10 * 0.5 * 4 = 200 J.

Answer: The work on lifting the chain in question is 200 J.