On the middle perpendicular to the segment AB, point M is marked so that AM = 3AB. the perimeter of the triangle ABM

On the middle perpendicular to the segment AB, point M is marked so that AM = 3AB. the perimeter of the triangle ABM is 28 cm. Find the length of the segment AB.

Given:
ABM – triangular
AM = 3AB
P = 28 cm.
Find: The length of the segment AB.
Decision:
Consider triangle AMB:
MH is the median and height, which means the triangle ABM is isosceles.
AM = MB = 3AB.
P = AM + MB + AB = 28 (cm)
3AB + 3AB + AB = 28
7AB = 28
AB = 4 (cm)
Answer: The length of the segment AB is 4 cm.



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