On the ordinate, find the point through which the line AB passes, if A (2; 8); B (-3; -2).

An equation of a straight line passing through points with coordinates (x0; y0) and (x1; y1) is compiled according to the formula:

(x – x0) / (x1 – x0) = (y – y0) / (y1 – y0).

Therefore, we compose the equation of the straight line passing through these points with coordinates A (2; 8) and B (-3; -2) and get:

(x – 2) / (- 3 – 2) = (y – 8) / (- 2 – 8);

(x – 2) / – 5 = (y – 8) / – 1.

Find a point on the ordinate, that is, x = 0 and get:

(0 – 2) / – 5 = (y – 8) / – 1;

-2 / -5 = – (y-8);

2/5 = -y + 8;

y = 8 – 2/5;

y = 7 5/5 – 2/5;

y = 7 3/5.

Answer: (0; 7 3/5).