On the path of 60 m, the speed of the body decreased 3 times in 20 s. Determine the speed of the body

| February 7, 2021 | education

On the path of 60 m, the speed of the body decreased 3 times in 20 s. Determine the speed of the body at the end of the path, considering the acceleration constant.

Since with uniformly accelerated motion the speed of the body has decreased by 3 times, then we take the speed at the beginning of the considered interval Vо = 3x m / s, and at the end V = x m / s. Assuming the acceleration to be constant, you can use the formula for the path for uniformly accelerated motion: S = (V + Vо) • t / 2, where the change in speed occurred in t = 20 seconds on the path S = 60 m. Substitute the values of physical quantities from the condition of the problem: 60 m = (x m / s + 3x m / s) • 20 s / 2; solve the resulting equation: 120 = 80x; x = 120: 80; V = x = 1.5 m / s.
Answer: the speed of the body at the end of the path will be 1.5 m / s.



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