On the segment AC 60 cm long, points E and F were marked so that AE 32, FC 34 cm. What is the length of the segment EF?

Knowing AC and AE, we find EC:

AC – AE = EC = 60cm – 32cm = 28cm.

Knowing AC and FC, we find AF:

AC – FC = AF = 60cm – 34cm = 26cm.

The segment AC can be represented from the sum of the lengths of the segments AF, EF, EC.

So EF = AC – AF – EC = 60cm – 26cm – 28cm = 6cm.

Answer: 6 cm.



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